Base | Representation |
---|---|
bin | 101111101011011001… |
… | …010100101001010101 |
3 | 11220010210101210200222 |
4 | 233223121110221111 |
5 | 1314321121033211 |
6 | 35303531244125 |
7 | 3461430114161 |
oct | 575331245125 |
9 | 156123353628 |
10 | 51193924181 |
11 | 1a7906a9a54 |
12 | 9b088a9645 |
13 | 4a9b21783a |
14 | 269911bca1 |
15 | 14e95d01db |
hex | beb654a55 |
51193924181 has 2 divisors, whose sum is σ = 51193924182. Its totient is φ = 51193924180.
The previous prime is 51193924153. The next prime is 51193924189. The reversal of 51193924181 is 18142939115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 46670689156 + 4523235025 = 216034^2 + 67255^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51193924181 is a prime.
It is a super-2 number, since 2×511939241812 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51193924189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25596962090 + 25596962091.
It is an arithmetic number, because the mean of its divisors is an integer number (25596962091).
Almost surely, 251193924181 is an apocalyptic number.
It is an amenable number.
51193924181 is a deficient number, since it is larger than the sum of its proper divisors (1).
51193924181 is an equidigital number, since it uses as much as digits as its factorization.
51193924181 is an evil number, because the sum of its binary digits is even.
The product of its digits is 77760, while the sum is 44.
The spelling of 51193924181 in words is "fifty-one billion, one hundred ninety-three million, nine hundred twenty-four thousand, one hundred eighty-one".
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