Base | Representation |
---|---|
bin | 1001100010010110… |
… | …10010110000101011 |
3 | 111012211012112010102 |
4 | 10301023102300223 |
5 | 40441210330212 |
6 | 2204015340015 |
7 | 240610243445 |
oct | 46113226053 |
9 | 14184175112 |
10 | 5120011307 |
11 | 2198127304 |
12 | baa82160b |
13 | 63798a9b8 |
14 | 367dc1495 |
15 | 1ee7605c2 |
hex | 1312d2c2b |
5120011307 has 2 divisors, whose sum is σ = 5120011308. Its totient is φ = 5120011306.
The previous prime is 5120011297. The next prime is 5120011319. The reversal of 5120011307 is 7031100215.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5120011307 - 24 = 5120011291 is a prime.
It is not a weakly prime, because it can be changed into another prime (5120017307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560005653 + 2560005654.
It is an arithmetic number, because the mean of its divisors is an integer number (2560005654).
Almost surely, 25120011307 is an apocalyptic number.
5120011307 is a deficient number, since it is larger than the sum of its proper divisors (1).
5120011307 is an equidigital number, since it uses as much as digits as its factorization.
5120011307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 210, while the sum is 20.
The square root of 5120011307 is about 71554.2542900141. The cubic root of 5120011307 is about 1723.5490207846.
The spelling of 5120011307 in words is "five billion, one hundred twenty million, eleven thousand, three hundred seven".
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