Base | Representation |
---|---|
bin | 1001100010010110… |
… | …10010110000110111 |
3 | 111012211012112010212 |
4 | 10301023102300313 |
5 | 40441210330234 |
6 | 2204015340035 |
7 | 240610243463 |
oct | 46113226067 |
9 | 14184175125 |
10 | 5120011319 |
11 | 2198127315 |
12 | baa82161b |
13 | 63798a9c7 |
14 | 367dc14a3 |
15 | 1ee7605ce |
hex | 1312d2c37 |
5120011319 has 2 divisors, whose sum is σ = 5120011320. Its totient is φ = 5120011318.
The previous prime is 5120011307. The next prime is 5120011321. The reversal of 5120011319 is 9131100215.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5120011319 - 28 = 5120011063 is a prime.
It is a super-2 number, since 2×51200113192 = 52429031813376239522, which contains 22 as substring.
Together with 5120011321, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 5120011294 and 5120011303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5120011399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560005659 + 2560005660.
It is an arithmetic number, because the mean of its divisors is an integer number (2560005660).
Almost surely, 25120011319 is an apocalyptic number.
5120011319 is a deficient number, since it is larger than the sum of its proper divisors (1).
5120011319 is an equidigital number, since it uses as much as digits as its factorization.
5120011319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 270, while the sum is 23.
The square root of 5120011319 is about 71554.2543738665. The cubic root of 5120011319 is about 1723.5490221311.
The spelling of 5120011319 in words is "five billion, one hundred twenty million, eleven thousand, three hundred nineteen".
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