Base | Representation |
---|---|
bin | 1110111001101011110… |
… | …01010001001001001101 |
3 | 1210221120112022210210111 |
4 | 13130311321101021031 |
5 | 31342041330004401 |
6 | 1031113442440021 |
7 | 51663653232232 |
oct | 7346571211115 |
9 | 1727515283714 |
10 | 512005313101 |
11 | 18815a718967 |
12 | 83291663011 |
13 | 39388422a39 |
14 | 1aad1825789 |
15 | d4b9aa2e51 |
hex | 7735e5124d |
512005313101 has 2 divisors, whose sum is σ = 512005313102. Its totient is φ = 512005313100.
The previous prime is 512005313093. The next prime is 512005313107. The reversal of 512005313101 is 101313500215.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 351263655625 + 160741657476 = 592675^2 + 400926^2 .
It is a cyclic number.
It is not a de Polignac number, because 512005313101 - 23 = 512005313093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (512005313107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256002656550 + 256002656551.
It is an arithmetic number, because the mean of its divisors is an integer number (256002656551).
Almost surely, 2512005313101 is an apocalyptic number.
It is an amenable number.
512005313101 is a deficient number, since it is larger than the sum of its proper divisors (1).
512005313101 is an equidigital number, since it uses as much as digits as its factorization.
512005313101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 450, while the sum is 22.
Adding to 512005313101 its reverse (101313500215), we get a palindrome (613318813316).
The spelling of 512005313101 in words is "five hundred twelve billion, five million, three hundred thirteen thousand, one hundred one".
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