512013412026541 has 2 divisors, whose sum is σ = 512013412026542. Its totient is φ = 512013412026540.

The previous prime is 512013412026419. The next prime is 512013412026689. The reversal of 512013412026541 is 145620214310215.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 471301087680900 + 40712324345641 = 21709470^2 + 6380621^2 .

It is a cyclic number.

It is not a de Polignac number, because 512013412026541 - 2¹¹ = 512013412024493 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 512013412026541.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (512013412029541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256006706013270 + 256006706013271.

It is an arithmetic number, because the mean of its divisors is an integer number (256006706013271).

Almost surely, 2^{512013412026541} is an apocalyptic number.

It is an amenable number.

512013412026541 is a deficient number, since it is larger than the sum of its proper divisors (1).

512013412026541 is an equidigital number, since it uses as much as digits as its factorization.

512013412026541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 57600, while the sum is 37.

Adding to 512013412026541 its reverse (145620214310215), we get a palindrome (657633626336756).

The spelling of 512013412026541 in words is "five hundred twelve trillion, thirteen billion, four hundred twelve million, twenty-six thousand, five hundred forty-one".