Base | Representation |
---|---|
bin | 111010001101011000110100… |
… | …1100010110100100010101111 |
3 | 2111010220000010000202021211210 |
4 | 1310122301221202310202233 |
5 | 1014102311431434322133 |
6 | 5012543414142045503 |
7 | 212563514442346410 |
oct | 16432615142644257 |
9 | 2433800100667753 |
10 | 512013412026543 |
11 | 139163739a21729 |
12 | 49513767879893 |
13 | 18c9087191794b |
14 | 906181d3b9807 |
15 | 3e2d99d00c763 |
hex | 1d1ac698b48af |
512013412026543 has 16 divisors (see below), whose sum is σ = 807114738170880. Its totient is φ = 282490158359136.
The previous prime is 512013412026541. The next prime is 512013412026689. The reversal of 512013412026543 is 345620214310215.
It is not a de Polignac number, because 512013412026543 - 21 = 512013412026541 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (512013412026541) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 420372258855 + ... + 420372260072.
It is an arithmetic number, because the mean of its divisors is an integer number (50444671135680).
Almost surely, 2512013412026543 is an apocalyptic number.
512013412026543 is a deficient number, since it is larger than the sum of its proper divisors (295101326144337).
512013412026543 is a wasteful number, since it uses less digits than its factorization.
512013412026543 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 840744518966.
The product of its (nonzero) digits is 172800, while the sum is 39.
Adding to 512013412026543 its reverse (345620214310215), we get a palindrome (857633626336758).
The spelling of 512013412026543 in words is "five hundred twelve trillion, thirteen billion, four hundred twelve million, twenty-six thousand, five hundred forty-three".
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