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51201641 = 65997759
BaseRepresentation
bin1100001101010…
…0011001101001
310120100022110002
43003110121221
5101101423031
65025232345
71161130631
oct303243151
9116308402
1051201641
11269a1607
12151926b5
13a7b933a
146b2b6c1
154765ccb
hex30d4669

51201641 has 4 divisors (see below), whose sum is σ = 51216000. Its totient is φ = 51187284.

The previous prime is 51201613. The next prime is 51201643. The reversal of 51201641 is 14610215.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 14610215 = 52922043.

It is a cyclic number.

It is not a de Polignac number, because 51201641 - 214 = 51185257 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51201643) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2720 + ... + 10478.

It is an arithmetic number, because the mean of its divisors is an integer number (12804000).

Almost surely, 251201641 is an apocalyptic number.

It is an amenable number.

51201641 is a deficient number, since it is larger than the sum of its proper divisors (14359).

51201641 is an equidigital number, since it uses as much as digits as its factorization.

51201641 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14358.

The product of its (nonzero) digits is 240, while the sum is 20.

The square root of 51201641 is about 7155.5321954415. The cubic root of 51201641 is about 371.3310737546.

Adding to 51201641 its reverse (14610215), we get a palindrome (65811856).

The spelling of 51201641 in words is "fifty-one million, two hundred one thousand, six hundred forty-one".

Divisors: 1 6599 7759 51201641