Base | Representation |
---|---|
bin | 10111010010001011011101… |
… | …11100111011011001100111 |
3 | 20201021212202000201010101121 |
4 | 23221011232330323121213 |
5 | 23202344014122220234 |
6 | 300521541155434411 |
7 | 13533143264061106 |
oct | 1351055674733147 |
9 | 221255660633347 |
10 | 51202166601319 |
11 | 15350798232888 |
12 | 58ab3a5bb5a07 |
13 | 2275460b473a6 |
14 | c902ab79803d |
15 | 5dbd44b6b4b4 |
hex | 2e916ef3b667 |
51202166601319 has 2 divisors, whose sum is σ = 51202166601320. Its totient is φ = 51202166601318.
The previous prime is 51202166601253. The next prime is 51202166601347. The reversal of 51202166601319 is 91310666120215.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51202166601319 - 27 = 51202166601191 is a prime.
It is a super-2 number, since 2×512021666013192 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51202166601389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25601083300659 + 25601083300660.
It is an arithmetic number, because the mean of its divisors is an integer number (25601083300660).
Almost surely, 251202166601319 is an apocalyptic number.
51202166601319 is a deficient number, since it is larger than the sum of its proper divisors (1).
51202166601319 is an equidigital number, since it uses as much as digits as its factorization.
51202166601319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 116640, while the sum is 43.
The spelling of 51202166601319 in words is "fifty-one trillion, two hundred two billion, one hundred sixty-six million, six hundred one thousand, three hundred nineteen".
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