Base | Representation |
---|---|
bin | 100101010000011000110… |
… | …0011000110000000000011 |
3 | 200010111201201201212002001 |
4 | 1022200301203012000003 |
5 | 1132343121132100120 |
6 | 14520143310404431 |
7 | 1035640041264403 |
oct | 112406143060003 |
9 | 20114651655061 |
10 | 5120432300035 |
11 | 16a46215a9038 |
12 | 6a845a500717 |
13 | 2b1b159bba70 |
14 | 139b8a2a0803 |
15 | 8d2da61ae0a |
hex | 4a8318c6003 |
5120432300035 has 32 divisors (see below), whose sum is σ = 6830905923072. Its totient is φ = 3659119626240.
The previous prime is 5120432300023. The next prime is 5120432300041. The reversal of 5120432300035 is 5300032340215.
It is not a de Polignac number, because 5120432300035 - 211 = 5120432297987 is a prime.
It is a super-2 number, since 2×51204323000352 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5120432299976 and 5120432300012.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 86206267 + ... + 86265643.
It is an arithmetic number, because the mean of its divisors is an integer number (213465810096).
Almost surely, 25120432300035 is an apocalyptic number.
5120432300035 is a deficient number, since it is larger than the sum of its proper divisors (1710473623037).
5120432300035 is a wasteful number, since it uses less digits than its factorization.
5120432300035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102223.
The product of its (nonzero) digits is 10800, while the sum is 28.
The spelling of 5120432300035 in words is "five trillion, one hundred twenty billion, four hundred thirty-two million, three hundred thousand, thirty-five".
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