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51211313 = 383133711
BaseRepresentation
bin1100001101011…
…0110000110001
310120100210201022
43003112300301
5101102230223
65025345225
71161201056
oct303266061
9116323638
1051211313
11269a88aa
1215198215
13a7c086a
146b3102d
154768ac8
hex30d6c31

51211313 has 4 divisors (see below), whose sum is σ = 51345408. Its totient is φ = 51077220.

The previous prime is 51211273. The next prime is 51211319. The reversal of 51211313 is 31311215.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51211313 - 212 = 51207217 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51211291 and 51211300.

It is not an unprimeable number, because it can be changed into a prime (51211319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66473 + ... + 67238.

It is an arithmetic number, because the mean of its divisors is an integer number (12836352).

Almost surely, 251211313 is an apocalyptic number.

It is an amenable number.

51211313 is a deficient number, since it is larger than the sum of its proper divisors (134095).

51211313 is a wasteful number, since it uses less digits than its factorization.

51211313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 134094.

The product of its digits is 90, while the sum is 17.

The square root of 51211313 is about 7156.2080042436. The cubic root of 51211313 is about 371.3544537866.

Adding to 51211313 its reverse (31311215), we get a palindrome (82522528).

The spelling of 51211313 in words is "fifty-one million, two hundred eleven thousand, three hundred thirteen".

Divisors: 1 383 133711 51211313