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5121342014043 = 36935292461489
BaseRepresentation
bin100101010000110011111…
…0001011000001001011011
3200010121002010112010002110
41022201213301120021123
51132402002023422133
614520413445003403
71036001425602003
oct112414761301133
920117063463073
105121342014043
1116a4a490656a2
126a86730b3563
132b1c2c306a88
14139c35029003
158d340415c63
hex4a867c5825b

5121342014043 has 8 divisors (see below), whose sum is σ = 6828468638800. Its totient is φ = 3414221699328.

The previous prime is 5121342014011. The next prime is 5121342014057. The reversal of 5121342014043 is 3404102431215.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5121342014043 - 25 = 5121342014011 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5121342014043.

It is not an unprimeable number, because it can be changed into a prime (5121342013043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 849843 + ... + 3311331.

It is an arithmetic number, because the mean of its divisors is an integer number (853558579850).

Almost surely, 25121342014043 is an apocalyptic number.

5121342014043 is a deficient number, since it is larger than the sum of its proper divisors (1707126624757).

5121342014043 is a wasteful number, since it uses less digits than its factorization.

5121342014043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3155021.

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 5121342014043 its reverse (3404102431215), we get a palindrome (8525444445258).

The spelling of 5121342014043 in words is "five trillion, one hundred twenty-one billion, three hundred forty-two million, fourteen thousand, forty-three".

Divisors: 1 3 693529 2080587 2461489 7384467 1707114004681 5121342014043