Base | Representation |
---|---|
bin | 100101010000110100101… |
… | …1100111101010101110111 |
3 | 200010121011002120220121221 |
4 | 1022201221130331111313 |
5 | 1132402031233401144 |
6 | 14520420333251211 |
7 | 1036002220400605 |
oct | 112415134752567 |
9 | 20117132526557 |
10 | 5121370215799 |
11 | 16a4a62a78032 |
12 | 6a8680633b07 |
13 | 2b1c350cc3c6 |
14 | 139c38a8a875 |
15 | 8d342b36d84 |
hex | 4a86973d577 |
5121370215799 has 2 divisors, whose sum is σ = 5121370215800. Its totient is φ = 5121370215798.
The previous prime is 5121370215739. The next prime is 5121370215809. The reversal of 5121370215799 is 9975120731215.
5121370215799 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5121370215799 - 225 = 5121336661367 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5121370215739) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560685107899 + 2560685107900.
It is an arithmetic number, because the mean of its divisors is an integer number (2560685107900).
Almost surely, 25121370215799 is an apocalyptic number.
5121370215799 is a deficient number, since it is larger than the sum of its proper divisors (1).
5121370215799 is an equidigital number, since it uses as much as digits as its factorization.
5121370215799 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1190700, while the sum is 52.
The spelling of 5121370215799 in words is "five trillion, one hundred twenty-one billion, three hundred seventy million, two hundred fifteen thousand, seven hundred ninety-nine".
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