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5121434502141 = 32958867063243
BaseRepresentation
bin100101010000110110101…
…0010001100001111111101
3200010121022120112222220120
41022201231102030033331
51132402144213032031
614520430551205153
71036003630666416
oct112415522141775
920117276488816
105121434502141
1116a4a96296341
126a869a0767b9
132b1c4551a369
14139c4342280d
158d3485d4a96
hex4a86d48c3fd

5121434502141 has 8 divisors (see below), whose sum is σ = 7064047589280. Its totient is φ = 3296555541552.

The previous prime is 5121434502131. The next prime is 5121434502143. The reversal of 5121434502141 is 1412054341215.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5121434502141 - 27 = 5121434502013 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5121434502143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29433531535 + ... + 29433531708.

It is an arithmetic number, because the mean of its divisors is an integer number (883005948660).

Almost surely, 25121434502141 is an apocalyptic number.

It is an amenable number.

5121434502141 is a deficient number, since it is larger than the sum of its proper divisors (1942613087139).

5121434502141 is a wasteful number, since it uses less digits than its factorization.

5121434502141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58867063275.

The product of its (nonzero) digits is 19200, while the sum is 33.

Adding to 5121434502141 its reverse (1412054341215), we get a palindrome (6533488843356).

The spelling of 5121434502141 in words is "five trillion, one hundred twenty-one billion, four hundred thirty-four million, five hundred two thousand, one hundred forty-one".

Divisors: 1 3 29 87 58867063243 176601189729 1707144834047 5121434502141