Base | Representation |
---|---|
bin | 101111101100101011… |
… | …000010000110011111 |
3 | 11220012021201001012202 |
4 | 233230223002012133 |
5 | 1314342112002111 |
6 | 35310014322115 |
7 | 3462110145545 |
oct | 575453020637 |
9 | 156167631182 |
10 | 51215344031 |
11 | 1a7a17aa005 |
12 | 9b13ab933b |
13 | 4aa27a72c7 |
14 | 269bcd5d95 |
15 | 14eb411b3b |
hex | becac219f |
51215344031 has 2 divisors, whose sum is σ = 51215344032. Its totient is φ = 51215344030.
The previous prime is 51215344027. The next prime is 51215344057. The reversal of 51215344031 is 13044351215.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51215344031 - 22 = 51215344027 is a prime.
It is a super-2 number, since 2×512153440312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51215343985 and 51215344003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51215340031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25607672015 + 25607672016.
It is an arithmetic number, because the mean of its divisors is an integer number (25607672016).
Almost surely, 251215344031 is an apocalyptic number.
51215344031 is a deficient number, since it is larger than the sum of its proper divisors (1).
51215344031 is an equidigital number, since it uses as much as digits as its factorization.
51215344031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 51215344031 its reverse (13044351215), we get a palindrome (64259695246).
The spelling of 51215344031 in words is "fifty-one billion, two hundred fifteen million, three hundred forty-four thousand, thirty-one".
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