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512255431432102 = 2256127715716051
BaseRepresentation
bin111010001111001001100001…
…1000001100101011110100110
32111011202010210202221221111011
41310132103003001211132212
51014120243110421311402
65013250521345532434
7212620143061351111
oct16436230301453646
92434663722857434
10512255431432102
11139247343632186
124955264b64411a
1318caa6314993b7
14906d41bd35578
153e34e153b0ed7
hex1d1e4c30657a6

512255431432102 has 4 divisors (see below), whose sum is σ = 768383147148156. Its totient is φ = 256127715716050.

The previous prime is 512255431432091. The next prime is 512255431432159. The reversal of 512255431432102 is 201234134552215.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×5122554314321022 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128063857858024 + ... + 128063857858027.

It is an arithmetic number, because the mean of its divisors is an integer number (192095786787039).

Almost surely, 2512255431432102 is an apocalyptic number.

512255431432102 is a deficient number, since it is larger than the sum of its proper divisors (256127715716054).

512255431432102 is a wasteful number, since it uses less digits than its factorization.

512255431432102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 256127715716053.

The product of its (nonzero) digits is 288000, while the sum is 40.

Adding to 512255431432102 its reverse (201234134552215), we get a palindrome (713489565984317).

The spelling of 512255431432102 in words is "five hundred twelve trillion, two hundred fifty-five billion, four hundred thirty-one million, four hundred thirty-two thousand, one hundred two".

Divisors: 1 2 256127715716051 512255431432102