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512300117113 = 1129453764497
BaseRepresentation
bin1110111010001110111…
…01110110110001111001
31210222100002001101212121
413131013131312301321
531343142312221423
61031203013241241
752004163101161
oct7350735666171
91728302041777
10512300117113
111882a1073544
1283354333221
1339404521795
141ab1ca455a1
15d4d58d745d
hex7747776c79

512300117113 has 4 divisors (see below), whose sum is σ = 512753882740. Its totient is φ = 511846351488.

The previous prime is 512300117101. The next prime is 512300117129. The reversal of 512300117113 is 311711003215.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311711003215 = 562342200643.

It can be written as a sum of positive squares in 2 ways, for example, as 113132667904 + 399167449209 = 336352^2 + 631797^2 .

It is a cyclic number.

It is not a de Polignac number, because 512300117113 - 229 = 511763246201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (512000117113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226881120 + ... + 226883377.

It is an arithmetic number, because the mean of its divisors is an integer number (128188470685).

Almost surely, 2512300117113 is an apocalyptic number.

It is an amenable number.

512300117113 is a deficient number, since it is larger than the sum of its proper divisors (453765627).

512300117113 is a wasteful number, since it uses less digits than its factorization.

512300117113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 453765626.

The product of its (nonzero) digits is 630, while the sum is 25.

The spelling of 512300117113 in words is "five hundred twelve billion, three hundred million, one hundred seventeen thousand, one hundred thirteen".

Divisors: 1 1129 453764497 512300117113