Base | Representation |
---|---|
bin | 100101010001101110010… |
… | …1110101001110011111111 |
3 | 200010210010212210020011112 |
4 | 1022203130232221303333 |
5 | 1132420011340443424 |
6 | 14521340302112235 |
7 | 1036101153313412 |
oct | 112433456516377 |
9 | 20123125706145 |
10 | 5123304234239 |
11 | 16a5865748784 |
12 | 6a8b2027b67b |
13 | 2b21829b4009 |
14 | 139d7d88bb79 |
15 | 8d40781460e |
hex | 4a8dcba9cff |
5123304234239 has 2 divisors, whose sum is σ = 5123304234240. Its totient is φ = 5123304234238.
The previous prime is 5123304234227. The next prime is 5123304234329. The reversal of 5123304234239 is 9324324033215.
Together with next prime (5123304234329) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5123304234239 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5123304234196 and 5123304234205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5123304294239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2561652117119 + 2561652117120.
It is an arithmetic number, because the mean of its divisors is an integer number (2561652117120).
Almost surely, 25123304234239 is an apocalyptic number.
5123304234239 is a deficient number, since it is larger than the sum of its proper divisors (1).
5123304234239 is an equidigital number, since it uses as much as digits as its factorization.
5123304234239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 466560, while the sum is 41.
The spelling of 5123304234239 in words is "five trillion, one hundred twenty-three billion, three hundred four million, two hundred thirty-four thousand, two hundred thirty-nine".
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