Base | Representation |
---|---|
bin | 100101010001101111010… |
… | …0100100100001111110011 |
3 | 200010210020000221121222121 |
4 | 1022203132210210033303 |
5 | 1132420042244110220 |
6 | 14521343324415111 |
7 | 1036102010122534 |
oct | 112433644441763 |
9 | 20123200847877 |
10 | 5123335144435 |
11 | 16a588113aaa2 |
12 | 6a8b2a6a7497 |
13 | 2b2189217381 |
14 | 139d83a1668b |
15 | 8d40a3bceaa |
hex | 4a8de9243f3 |
5123335144435 has 16 divisors (see below), whose sum is σ = 6510341349792. Its totient is φ = 3857159923200.
The previous prime is 5123335144409. The next prime is 5123335144481. The reversal of 5123335144435 is 5344415333215.
It is not a de Polignac number, because 5123335144435 - 239 = 4573579330547 is a prime.
It is a super-2 number, since 2×51233351444352 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5123335144391 and 5123335144400.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2398161 + ... + 3999730.
It is an arithmetic number, because the mean of its divisors is an integer number (406896334362).
Almost surely, 25123335144435 is an apocalyptic number.
5123335144435 is a deficient number, since it is larger than the sum of its proper divisors (1387006205357).
5123335144435 is a wasteful number, since it uses less digits than its factorization.
5123335144435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6407334.
The product of its digits is 1296000, while the sum is 43.
The spelling of 5123335144435 in words is "five trillion, one hundred twenty-three billion, three hundred thirty-five million, one hundred forty-four thousand, four hundred thirty-five".
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