Base | Representation |
---|---|
bin | 100101010001101111010… |
… | …0100110101011110011001 |
3 | 200010210020001002012210011 |
4 | 1022203132210311132121 |
5 | 1132420042303340001 |
6 | 14521343330121521 |
7 | 1036102010535343 |
oct | 112433644653631 |
9 | 20123201065704 |
10 | 5123335215001 |
11 | 16a5881189013 |
12 | 6a8b2a7202a1 |
13 | 2b2189240523 |
14 | 139d83a34293 |
15 | 8d40a3d3d51 |
hex | 4a8de935799 |
5123335215001 has 2 divisors, whose sum is σ = 5123335215002. Its totient is φ = 5123335215000.
The previous prime is 5123335214953. The next prime is 5123335215007. The reversal of 5123335215001 is 1005125333215.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4172562009225 + 950773205776 = 2042685^2 + 975076^2 .
It is a cyclic number.
It is not a de Polignac number, because 5123335215001 - 215 = 5123335182233 is a prime.
It is not a weakly prime, because it can be changed into another prime (5123335215007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2561667607500 + 2561667607501.
It is an arithmetic number, because the mean of its divisors is an integer number (2561667607501).
Almost surely, 25123335215001 is an apocalyptic number.
It is an amenable number.
5123335215001 is a deficient number, since it is larger than the sum of its proper divisors (1).
5123335215001 is an equidigital number, since it uses as much as digits as its factorization.
5123335215001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13500, while the sum is 31.
The spelling of 5123335215001 in words is "five trillion, one hundred twenty-three billion, three hundred thirty-five million, two hundred fifteen thousand, one".
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