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5124025007 = 36713961921
BaseRepresentation
bin1001100010110101…
…00110101010101111
3111020002202102212222
410301122212222233
540443222300012
62204241345555
7240656331263
oct46132465257
914202672788
105124025007
11219a418912
12bb00382bb
1363876487a
143687480a3
151eeca4972
hex1316a6aaf

5124025007 has 4 divisors (see below), whose sum is σ = 5137987296. Its totient is φ = 5110062720.

The previous prime is 5124024989. The next prime is 5124025019. The reversal of 5124025007 is 7005204215.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5124025007 - 26 = 5124024943 is a prime.

It is a super-2 number, since 2×51240250072 = 52511264544722700098, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5124025087) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6980594 + ... + 6981327.

It is an arithmetic number, because the mean of its divisors is an integer number (1284496824).

Almost surely, 25124025007 is an apocalyptic number.

5124025007 is a deficient number, since it is larger than the sum of its proper divisors (13962289).

5124025007 is a wasteful number, since it uses less digits than its factorization.

5124025007 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13962288.

The product of its (nonzero) digits is 2800, while the sum is 26.

The square root of 5124025007 is about 71582.2953459862. The cubic root of 5124025007 is about 1723.9992803250. Note that the first 3 decimals are identical.

The spelling of 5124025007 in words is "five billion, one hundred twenty-four million, twenty-five thousand, seven".

Divisors: 1 367 13961921 5124025007