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5124080131 is a prime number
BaseRepresentation
bin1001100010110101…
…10100001000000011
3111020002212020111121
410301122310020003
540443231031011
62204242453111
7240656651062
oct46132641003
914202766447
105124080131
11219a456275
12bb0064197
136387839a1
143687601d9
151eecb5e71
hex1316b4203

5124080131 has 2 divisors, whose sum is σ = 5124080132. Its totient is φ = 5124080130.

The previous prime is 5124080089. The next prime is 5124080141. The reversal of 5124080131 is 1310804215.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5124080131 - 215 = 5124047363 is a prime.

It is a super-2 number, since 2×51240801312 = 52512394377817954322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5124080096 and 5124080105.

It is not a weakly prime, because it can be changed into another prime (5124080141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2562040065 + 2562040066.

It is an arithmetic number, because the mean of its divisors is an integer number (2562040066).

Almost surely, 25124080131 is an apocalyptic number.

5124080131 is a deficient number, since it is larger than the sum of its proper divisors (1).

5124080131 is an equidigital number, since it uses as much as digits as its factorization.

5124080131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960, while the sum is 25.

The square root of 5124080131 is about 71582.6803842941. The cubic root of 5124080131 is about 1724.0054625349.

Adding to 5124080131 its reverse (1310804215), we get a palindrome (6434884346).

The spelling of 5124080131 in words is "five billion, one hundred twenty-four million, eighty thousand, one hundred thirty-one".