Base | Representation |
---|---|
bin | 10111010011010011110111… |
… | …10000110011000000100011 |
3 | 20201102121001220202212220021 |
4 | 23221221323300303000203 |
5 | 23204013120233340231 |
6 | 300551450154454311 |
7 | 13536020434344526 |
oct | 1351517360630043 |
9 | 221377056685807 |
10 | 51241036230691 |
11 | 1536622411271a |
12 | 58b6a33434397 |
13 | 2279016974398 |
14 | c92117b9cbbd |
15 | 5dcd6c2bd811 |
hex | 2e9a7bc33023 |
51241036230691 has 2 divisors, whose sum is σ = 51241036230692. Its totient is φ = 51241036230690.
The previous prime is 51241036230647. The next prime is 51241036230701. The reversal of 51241036230691 is 19603263014215.
51241036230691 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51241036230691 - 211 = 51241036228643 is a prime.
It is not a weakly prime, because it can be changed into another prime (51241036230491) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25620518115345 + 25620518115346.
It is an arithmetic number, because the mean of its divisors is an integer number (25620518115346).
Almost surely, 251241036230691 is an apocalyptic number.
51241036230691 is a deficient number, since it is larger than the sum of its proper divisors (1).
51241036230691 is an equidigital number, since it uses as much as digits as its factorization.
51241036230691 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 233280, while the sum is 43.
The spelling of 51241036230691 in words is "fifty-one trillion, two hundred forty-one billion, thirty-six million, two hundred thirty thousand, six hundred ninety-one".
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