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51241225201321 is a prime number
BaseRepresentation
bin10111010011010100001110…
…00001101010011010101001
320201102121120002100120212111
423221222013001222122221
523204014012122420241
6300551521025042321
713536025220514361
oct1351520701523251
9221377502316774
1051241225201321
11153663108520a1
1258b6a867863a1
132279046b6941c
14c92134d0d9a1
155dcd7db99c81
hex2e9a8706a6a9

51241225201321 has 2 divisors, whose sum is σ = 51241225201322. Its totient is φ = 51241225201320.

The previous prime is 51241225201319. The next prime is 51241225201433. The reversal of 51241225201321 is 12310252214215.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 39696615275625 + 11544609925696 = 6300525^2 + 3397736^2 .

It is a cyclic number.

It is not a de Polignac number, because 51241225201321 - 21 = 51241225201319 is a prime.

Together with 51241225201319, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (51241225201021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25620612600660 + 25620612600661.

It is an arithmetic number, because the mean of its divisors is an integer number (25620612600661).

Almost surely, 251241225201321 is an apocalyptic number.

It is an amenable number.

51241225201321 is a deficient number, since it is larger than the sum of its proper divisors (1).

51241225201321 is an equidigital number, since it uses as much as digits as its factorization.

51241225201321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 51241225201321 its reverse (12310252214215), we get a palindrome (63551477415536).

The spelling of 51241225201321 in words is "fifty-one trillion, two hundred forty-one billion, two hundred twenty-five million, two hundred one thousand, three hundred twenty-one".