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5124333940697 is a prime number
BaseRepresentation
bin100101010010001101000…
…0110101010111111011001
3200010212210122100201212202
41022210122012222333121
51132424113442100242
614522030404215545
71036135525551146
oct112443206527731
920125718321782
105124333940697
1116a6243a11454
126a916909a5b5
132b22b812268a
1413a03a52d3cd
158d467e12932
hex4a91a1aafd9

5124333940697 has 2 divisors, whose sum is σ = 5124333940698. Its totient is φ = 5124333940696.

The previous prime is 5124333940679. The next prime is 5124333940771. The reversal of 5124333940697 is 7960493334215.

Together with previous prime (5124333940679) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4732521790096 + 391812150601 = 2175436^2 + 625949^2 .

It is a cyclic number.

It is not a de Polignac number, because 5124333940697 - 214 = 5124333924313 is a prime.

It is a super-2 number, since 2×51243339406972 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5124333940997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2562166970348 + 2562166970349.

It is an arithmetic number, because the mean of its divisors is an integer number (2562166970349).

Almost surely, 25124333940697 is an apocalyptic number.

It is an amenable number.

5124333940697 is a deficient number, since it is larger than the sum of its proper divisors (1).

5124333940697 is an equidigital number, since it uses as much as digits as its factorization.

5124333940697 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14696640, while the sum is 56.

The spelling of 5124333940697 in words is "five trillion, one hundred twenty-four billion, three hundred thirty-three million, nine hundred forty thousand, six hundred ninety-seven".