Base | Representation |
---|---|
bin | 100101010010001101000… |
… | …0110101011000100000101 |
3 | 200010212210122100202021212 |
4 | 1022210122012223010011 |
5 | 1132424113442102442 |
6 | 14522030404221205 |
7 | 1036135525552055 |
oct | 112443206530405 |
9 | 20125718322255 |
10 | 5124333940997 |
11 | 16a6243a116a7 |
12 | 6a916909a805 |
13 | 2b22b812285b |
14 | 13a03a52d565 |
15 | 8d467e12a82 |
hex | 4a91a1ab105 |
5124333940997 has 2 divisors, whose sum is σ = 5124333940998. Its totient is φ = 5124333940996.
The previous prime is 5124333940931. The next prime is 5124333941039. The reversal of 5124333940997 is 7990493334215.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5059467454276 + 64866486721 = 2249326^2 + 254689^2 .
It is a cyclic number.
It is not a de Polignac number, because 5124333940997 - 214 = 5124333924613 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5124333940697) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2562166970498 + 2562166970499.
It is an arithmetic number, because the mean of its divisors is an integer number (2562166970499).
Almost surely, 25124333940997 is an apocalyptic number.
It is an amenable number.
5124333940997 is a deficient number, since it is larger than the sum of its proper divisors (1).
5124333940997 is an equidigital number, since it uses as much as digits as its factorization.
5124333940997 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 22044960, while the sum is 59.
The spelling of 5124333940997 in words is "five trillion, one hundred twenty-four billion, three hundred thirty-three million, nine hundred forty thousand, nine hundred ninety-seven".
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