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5124333940997 is a prime number
BaseRepresentation
bin100101010010001101000…
…0110101011000100000101
3200010212210122100202021212
41022210122012223010011
51132424113442102442
614522030404221205
71036135525552055
oct112443206530405
920125718322255
105124333940997
1116a6243a116a7
126a916909a805
132b22b812285b
1413a03a52d565
158d467e12a82
hex4a91a1ab105

5124333940997 has 2 divisors, whose sum is σ = 5124333940998. Its totient is φ = 5124333940996.

The previous prime is 5124333940931. The next prime is 5124333941039. The reversal of 5124333940997 is 7990493334215.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5059467454276 + 64866486721 = 2249326^2 + 254689^2 .

It is a cyclic number.

It is not a de Polignac number, because 5124333940997 - 214 = 5124333924613 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5124333940697) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2562166970498 + 2562166970499.

It is an arithmetic number, because the mean of its divisors is an integer number (2562166970499).

Almost surely, 25124333940997 is an apocalyptic number.

It is an amenable number.

5124333940997 is a deficient number, since it is larger than the sum of its proper divisors (1).

5124333940997 is an equidigital number, since it uses as much as digits as its factorization.

5124333940997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 22044960, while the sum is 59.

The spelling of 5124333940997 in words is "five trillion, one hundred twenty-four billion, three hundred thirty-three million, nine hundred forty thousand, nine hundred ninety-seven".