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5124434602451 is a prime number
BaseRepresentation
bin100101010010010000000…
…0110101010100111010011
3200010220001122202212211212
41022210200012222213103
51132424320224234301
614522044401530335
71036141160300513
oct112444006524723
920126048685755
105124434602451
1116a629581508a
126a91969439ab
132b2302c38448
1413a049a53843
158d471b984bb
hex4a9201aa9d3

5124434602451 has 2 divisors, whose sum is σ = 5124434602452. Its totient is φ = 5124434602450.

The previous prime is 5124434602421. The next prime is 5124434602453. The reversal of 5124434602451 is 1542064344215.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5124434602451 is a prime.

Together with 5124434602453, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5124434602399 and 5124434602408.

It is not a weakly prime, because it can be changed into another prime (5124434602453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2562217301225 + 2562217301226.

It is an arithmetic number, because the mean of its divisors is an integer number (2562217301226).

Almost surely, 25124434602451 is an apocalyptic number.

5124434602451 is a deficient number, since it is larger than the sum of its proper divisors (1).

5124434602451 is an equidigital number, since it uses as much as digits as its factorization.

5124434602451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 460800, while the sum is 41.

Adding to 5124434602451 its reverse (1542064344215), we get a palindrome (6666498946666).

The spelling of 5124434602451 in words is "five trillion, one hundred twenty-four billion, four hundred thirty-four million, six hundred two thousand, four hundred fifty-one".