Base | Representation |
---|---|
bin | 10111010011011011010000… |
… | …10100100111011010010111 |
3 | 20201102222022111210110100202 |
4 | 23221231220110213122113 |
5 | 23204044232242341401 |
6 | 300553344052131115 |
7 | 13536220665606110 |
oct | 1351555024473227 |
9 | 221388274713322 |
10 | 51245005043351 |
11 | 15367980435389 |
12 | 58b7760606a9b |
13 | 22794c9c96542 |
14 | c923b2d15207 |
15 | 5dd00093306b |
hex | 2e9b68527697 |
51245005043351 has 32 divisors (see below), whose sum is σ = 62115684246528. Its totient is φ = 41324583421440.
The previous prime is 51245005043347. The next prime is 51245005043357. The reversal of 51245005043351 is 15334050054215.
It is a cyclic number.
It is not a de Polignac number, because 51245005043351 - 22 = 51245005043347 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51245005043357) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 531886655 + ... + 531982991.
It is an arithmetic number, because the mean of its divisors is an integer number (1941115132704).
Almost surely, 251245005043351 is an apocalyptic number.
51245005043351 is a deficient number, since it is larger than the sum of its proper divisors (10870679203177).
51245005043351 is a wasteful number, since it uses less digits than its factorization.
51245005043351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 150591.
The product of its (nonzero) digits is 180000, while the sum is 38.
Adding to 51245005043351 its reverse (15334050054215), we get a palindrome (66579055097566).
The spelling of 51245005043351 in words is "fifty-one trillion, two hundred forty-five billion, five million, forty-three thousand, three hundred fifty-one".
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