Base | Representation |
---|---|
bin | 100101010010011110001… |
… | …0011111001110101001111 |
3 | 200010221021122020120110022 |
4 | 1022210330103321311033 |
5 | 1132431302401202303 |
6 | 14522203344532355 |
7 | 1036155664560416 |
oct | 112447423716517 |
9 | 20127248216408 |
10 | 5124907834703 |
11 | 16a6508959518 |
12 | 6a92a93210bb |
13 | 2b2379caa827 |
14 | 13a09283c47d |
15 | 8d49d4c5438 |
hex | 4a93c4f9d4f |
5124907834703 has 4 divisors (see below), whose sum is σ = 5125687057920. Its totient is φ = 5124128611488.
The previous prime is 5124907834679. The next prime is 5124907834729. The reversal of 5124907834703 is 3074387094215.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5124907834703 - 220 = 5124906786127 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5124904834703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 389601743 + ... + 389614896.
It is an arithmetic number, because the mean of its divisors is an integer number (1281421764480).
Almost surely, 25124907834703 is an apocalyptic number.
5124907834703 is a deficient number, since it is larger than the sum of its proper divisors (779223217).
5124907834703 is an equidigital number, since it uses as much as digits as its factorization.
5124907834703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 779223216.
The product of its (nonzero) digits is 5080320, while the sum is 53.
The spelling of 5124907834703 in words is "five trillion, one hundred twenty-four billion, nine hundred seven million, eight hundred thirty-four thousand, seven hundred three".
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