Base | Representation |
---|---|
bin | 111010010001000101010101… |
… | …1001111100101000001100111 |
3 | 2111012200120010000222222122121 |
4 | 1310202022223033211001213 |
5 | 1014134122131011410211 |
6 | 5014013013313410411 |
7 | 212645305050431101 |
oct | 16442125317450147 |
9 | 2435616100888577 |
10 | 512521320419431 |
11 | 13933a086a78814 |
12 | 49596095269a07 |
13 | 18cc972631322b |
14 | 907c242a5c571 |
15 | 3e3bcc8093271 |
hex | 1d222ab3e5067 |
512521320419431 has 2 divisors, whose sum is σ = 512521320419432. Its totient is φ = 512521320419430.
The previous prime is 512521320419419. The next prime is 512521320419461. The reversal of 512521320419431 is 134914023125215.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-512521320419431 is a prime.
It is a super-2 number, since 2×5125213204194312 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (512521320419401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256260660209715 + 256260660209716.
It is an arithmetic number, because the mean of its divisors is an integer number (256260660209716).
Almost surely, 2512521320419431 is an apocalyptic number.
512521320419431 is a deficient number, since it is larger than the sum of its proper divisors (1).
512521320419431 is an equidigital number, since it uses as much as digits as its factorization.
512521320419431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 43.
The spelling of 512521320419431 in words is "five hundred twelve trillion, five hundred twenty-one billion, three hundred twenty million, four hundred nineteen thousand, four hundred thirty-one".
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