Base | Representation |
---|---|
bin | 100101010010101011001… |
… | …0101011001101110110001 |
3 | 200010222102001210011122011 |
4 | 1022211112111121232301 |
5 | 1132433201133410441 |
6 | 14522314542442521 |
7 | 1036202545611061 |
oct | 112452625315661 |
9 | 20128361704564 |
10 | 5125344435121 |
11 | 16a6712352909 |
12 | 6a93ab593441 |
13 | 2b2419595481 |
14 | 13a0d480d3a1 |
15 | 8d4c69b8581 |
hex | 4a956559bb1 |
5125344435121 has 2 divisors, whose sum is σ = 5125344435122. Its totient is φ = 5125344435120.
The previous prime is 5125344435097. The next prime is 5125344435143. The reversal of 5125344435121 is 1215344435215.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2629067673600 + 2496276761521 = 1621440^2 + 1579961^2 .
It is a cyclic number.
It is not a de Polignac number, because 5125344435121 - 25 = 5125344435089 is a prime.
It is not a weakly prime, because it can be changed into another prime (5125344435151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2562672217560 + 2562672217561.
It is an arithmetic number, because the mean of its divisors is an integer number (2562672217561).
Almost surely, 25125344435121 is an apocalyptic number.
It is an amenable number.
5125344435121 is a deficient number, since it is larger than the sum of its proper divisors (1).
5125344435121 is an equidigital number, since it uses as much as digits as its factorization.
5125344435121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 288000, while the sum is 40.
The spelling of 5125344435121 in words is "five trillion, one hundred twenty-five billion, three hundred forty-four million, four hundred thirty-five thousand, one hundred twenty-one".
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