Base | Representation |
---|---|
bin | 100101010010101011001… |
… | …0101011001101111001111 |
3 | 200010222102001210011200021 |
4 | 1022211112111121233033 |
5 | 1132433201133411101 |
6 | 14522314542443011 |
7 | 1036202545611133 |
oct | 112452625315717 |
9 | 20128361704607 |
10 | 5125344435151 |
11 | 16a6712352936 |
12 | 6a93ab593467 |
13 | 2b24195954a5 |
14 | 13a0d480d3c3 |
15 | 8d4c69b85a1 |
hex | 4a956559bcf |
5125344435151 has 2 divisors, whose sum is σ = 5125344435152. Its totient is φ = 5125344435150.
The previous prime is 5125344435143. The next prime is 5125344435163. The reversal of 5125344435151 is 1515344435215.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5125344435151 - 23 = 5125344435143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5125344435098 and 5125344435107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5125344435121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2562672217575 + 2562672217576.
It is an arithmetic number, because the mean of its divisors is an integer number (2562672217576).
Almost surely, 25125344435151 is an apocalyptic number.
5125344435151 is a deficient number, since it is larger than the sum of its proper divisors (1).
5125344435151 is an equidigital number, since it uses as much as digits as its factorization.
5125344435151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 720000, while the sum is 43.
The spelling of 5125344435151 in words is "five trillion, one hundred twenty-five billion, three hundred forty-four million, four hundred thirty-five thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •