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5125422404033 is a prime number
BaseRepresentation
bin100101010010101101011…
…1110110101000111000001
3200010222121111111101212122
41022211122332311013001
51132433331113412113
614522330405534025
71036204513414511
oct112453276650701
920128544441778
105125422404033
1116a6752367028
126a9411714315
132b242c794219
1413a100d07841
158d4cd76a408
hex4a95afb51c1

5125422404033 has 2 divisors, whose sum is σ = 5125422404034. Its totient is φ = 5125422404032.

The previous prime is 5125422404009. The next prime is 5125422404059. The reversal of 5125422404033 is 3304042245215.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4019174924944 + 1106247479089 = 2004788^2 + 1051783^2 .

It is a cyclic number.

It is not a de Polignac number, because 5125422404033 - 214 = 5125422387649 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5125422403984 and 5125422404002.

It is not a weakly prime, because it can be changed into another prime (5125422404633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2562711202016 + 2562711202017.

It is an arithmetic number, because the mean of its divisors is an integer number (2562711202017).

Almost surely, 25125422404033 is an apocalyptic number.

It is an amenable number.

5125422404033 is a deficient number, since it is larger than the sum of its proper divisors (1).

5125422404033 is an equidigital number, since it uses as much as digits as its factorization.

5125422404033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 115200, while the sum is 35.

Adding to 5125422404033 its reverse (3304042245215), we get a palindrome (8429464649248).

The spelling of 5125422404033 in words is "five trillion, one hundred twenty-five billion, four hundred twenty-two million, four hundred four thousand, thirty-three".