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5128515807117 = 31709505269039
BaseRepresentation
bin100101010100001001101…
…0111001110011110001101
3200011021121002021120011020
41022220103113032132031
51133011200021311432
614524001352144353
71036344255045423
oct112502327163615
920137532246136
105128515807117
1116a7a9a5225aa
126a9b356980b9
132b280361c651
1413a315aa5113
158d61010e22c
hex4aa135ce78d

5128515807117 has 4 divisors (see below), whose sum is σ = 6838021076160. Its totient is φ = 3419010538076.

The previous prime is 5128515807049. The next prime is 5128515807127. The reversal of 5128515807117 is 7117085158215.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5128515807117 - 228 = 5128247371661 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5128515807117.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5128515807127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 854752634517 + ... + 854752634522.

It is an arithmetic number, because the mean of its divisors is an integer number (1709505269040).

Almost surely, 25128515807117 is an apocalyptic number.

It is an amenable number.

5128515807117 is a deficient number, since it is larger than the sum of its proper divisors (1709505269043).

5128515807117 is a wasteful number, since it uses less digits than its factorization.

5128515807117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1709505269042.

The product of its (nonzero) digits is 784000, while the sum is 51.

The spelling of 5128515807117 in words is "five trillion, one hundred twenty-eight billion, five hundred fifteen million, eight hundred seven thousand, one hundred seventeen".

Divisors: 1 3 1709505269039 5128515807117