Base | Representation |
---|---|
bin | 1110111011010110111… |
… | …01111110110111010011 |
3 | 1211000220011121102210101 |
4 | 13131223131332313103 |
5 | 31400411424130003 |
6 | 1031342551313231 |
7 | 52025146112536 |
oct | 7355335766723 |
9 | 1730804542711 |
10 | 512904130003 |
11 | 188581012351 |
12 | 834a267b817 |
13 | 3949c6c3a65 |
14 | 1ab78d54a1d |
15 | d51d94911d |
hex | 776b77edd3 |
512904130003 has 4 divisors (see below), whose sum is σ = 513073800288. Its totient is φ = 512734459720.
The previous prime is 512904129977. The next prime is 512904130021. The reversal of 512904130003 is 300031409215.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 300031409215 = 5 ⋅60006281843.
It is a cyclic number.
It is not a de Polignac number, because 512904130003 - 229 = 512367259091 is a prime.
It is a super-3 number, since 3×5129041300033 (a number of 36 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (512904130703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84830608 + ... + 84836653.
It is an arithmetic number, because the mean of its divisors is an integer number (128268450072).
Almost surely, 2512904130003 is an apocalyptic number.
512904130003 is a deficient number, since it is larger than the sum of its proper divisors (169670285).
512904130003 is a wasteful number, since it uses less digits than its factorization.
512904130003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 169670284.
The product of its (nonzero) digits is 3240, while the sum is 28.
Adding to 512904130003 its reverse (300031409215), we get a palindrome (812935539218).
The spelling of 512904130003 in words is "five hundred twelve billion, nine hundred four million, one hundred thirty thousand, three".
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