Base | Representation |
---|---|
bin | 100101010100110110101… |
… | …1010111011001001101111 |
3 | 200011102111101100012012211 |
4 | 1022221231122323021233 |
5 | 1133022243320212444 |
6 | 14524411324311251 |
7 | 1036426562460640 |
oct | 112515532731157 |
9 | 20142441305184 |
10 | 5130026725999 |
11 | 16a86a539029a |
12 | 6aa2976a2527 |
13 | 2b29b46657a6 |
14 | 13a41a60b6c7 |
15 | 8d69cab3c34 |
hex | 4aa6d6bb26f |
5130026725999 has 4 divisors (see below), whose sum is σ = 5862887686864. Its totient is φ = 4397165765136.
The previous prime is 5130026725969. The next prime is 5130026726039. The reversal of 5130026725999 is 9995276200315.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5130026725999 - 211 = 5130026723951 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5130026725969) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 366430480422 + ... + 366430480435.
It is an arithmetic number, because the mean of its divisors is an integer number (1465721921716).
Almost surely, 25130026725999 is an apocalyptic number.
5130026725999 is a deficient number, since it is larger than the sum of its proper divisors (732860960865).
5130026725999 is an equidigital number, since it uses as much as digits as its factorization.
5130026725999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 732860960864.
The product of its (nonzero) digits is 9185400, while the sum is 58.
The spelling of 5130026725999 in words is "five trillion, one hundred thirty billion, twenty-six million, seven hundred twenty-five thousand, nine hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •