Base | Representation |
---|---|
bin | 1100001110110… |
… | …0100000101101 |
3 | 10120112022220201 |
4 | 3003230200231 |
5 | 101113103042 |
6 | 5031313501 |
7 | 1162021561 |
oct | 303544055 |
9 | 116468821 |
10 | 51300397 |
11 | 26a59825 |
12 | 1521b891 |
13 | a822285 |
14 | 6b556a1 |
15 | 47851b7 |
hex | 30ec82d |
51300397 has 2 divisors, whose sum is σ = 51300398. Its totient is φ = 51300396.
The previous prime is 51300377. The next prime is 51300433. The reversal of 51300397 is 79300315.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 48038761 + 3261636 = 6931^2 + 1806^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51300397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51300377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25650198 + 25650199.
It is an arithmetic number, because the mean of its divisors is an integer number (25650199).
Almost surely, 251300397 is an apocalyptic number.
It is an amenable number.
51300397 is a deficient number, since it is larger than the sum of its proper divisors (1).
51300397 is an equidigital number, since it uses as much as digits as its factorization.
51300397 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2835, while the sum is 28.
The square root of 51300397 is about 7162.4295459013. The cubic root of 51300397 is about 371.5696573841.
The spelling of 51300397 in words is "fifty-one million, three hundred thousand, three hundred ninety-seven".
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