Base | Representation |
---|---|
bin | 10111010101000101110110… |
… | …11101101010110000101101 |
3 | 20201122110000221010002022111 |
4 | 23222202323131222300231 |
5 | 23211013434013001031 |
6 | 301035530550044021 |
7 | 13543315124142262 |
oct | 1352427335526055 |
9 | 221573027102274 |
10 | 51302234500141 |
11 | 1538a178a24309 |
12 | 5906872649611 |
13 | 2281a1a73b141 |
14 | c95081851269 |
15 | 5de74ed191b1 |
hex | 2ea8bb76ac2d |
51302234500141 has 2 divisors, whose sum is σ = 51302234500142. Its totient is φ = 51302234500140.
The previous prime is 51302234500133. The next prime is 51302234500219. The reversal of 51302234500141 is 14100543220315.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50076087990916 + 1226146509225 = 7076446^2 + 1107315^2 .
It is a cyclic number.
It is not a de Polignac number, because 51302234500141 - 23 = 51302234500133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51302234500841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25651117250070 + 25651117250071.
It is an arithmetic number, because the mean of its divisors is an integer number (25651117250071).
Almost surely, 251302234500141 is an apocalyptic number.
It is an amenable number.
51302234500141 is a deficient number, since it is larger than the sum of its proper divisors (1).
51302234500141 is an equidigital number, since it uses as much as digits as its factorization.
51302234500141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 51302234500141 its reverse (14100543220315), we get a palindrome (65402777720456).
The spelling of 51302234500141 in words is "fifty-one trillion, three hundred two billion, two hundred thirty-four million, five hundred thousand, one hundred forty-one".
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