Base | Representation |
---|---|
bin | 100101010100111111110… |
… | …0001011011110100001101 |
3 | 200011110021112210120112220 |
4 | 1022221333201123310031 |
5 | 1133023404042010131 |
6 | 14524501413445553 |
7 | 1036440241034412 |
oct | 112517741336415 |
9 | 20143245716486 |
10 | 5130330422541 |
11 | 16a8840859a75 |
12 | 6aa3613408b9 |
13 | 2b2a32558c9c |
14 | 13a448aa4109 |
15 | 8d6b95a2e96 |
hex | 4aa7f85bd0d |
5130330422541 has 8 divisors (see below), whose sum is σ = 6840645813600. Its totient is φ = 3420117656592.
The previous prime is 5130330422533. The next prime is 5130330422599. The reversal of 5130330422541 is 1452240330315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5130330422541 - 23 = 5130330422533 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5130330422531) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25539555 + ... + 25739648.
It is an arithmetic number, because the mean of its divisors is an integer number (855080726700).
Almost surely, 25130330422541 is an apocalyptic number.
It is an amenable number.
5130330422541 is a deficient number, since it is larger than the sum of its proper divisors (1710315391059).
5130330422541 is a wasteful number, since it uses less digits than its factorization.
5130330422541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51312555.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 5130330422541 its reverse (1452240330315), we get a palindrome (6582570752856).
The spelling of 5130330422541 in words is "five trillion, one hundred thirty billion, three hundred thirty million, four hundred twenty-two thousand, five hundred forty-one".
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