Base | Representation |
---|---|
bin | 101111110010000010… |
… | …100101010000011111 |
3 | 11220102120011112110210 |
4 | 233302002211100133 |
5 | 1320033140402143 |
6 | 35322552503503 |
7 | 3464252506431 |
oct | 576202452037 |
9 | 156376145423 |
10 | 51305403423 |
11 | 1a838620a5a |
12 | 9b3a0aab93 |
13 | 4ab834a2a1 |
14 | 26a9c5a651 |
15 | 15042a1033 |
hex | bf20a541f |
51305403423 has 16 divisors (see below), whose sum is σ = 70863055200. Its totient is φ = 32994424320.
The previous prime is 51305403397. The next prime is 51305403433. The reversal of 51305403423 is 32430450315.
51305403423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 51305403423 - 213 = 51305395231 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51305403433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2332408 + ... + 2354301.
It is an arithmetic number, because the mean of its divisors is an integer number (4428940950).
Almost surely, 251305403423 is an apocalyptic number.
51305403423 is a deficient number, since it is larger than the sum of its proper divisors (19557651777).
51305403423 is a wasteful number, since it uses less digits than its factorization.
51305403423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4686842.
The product of its (nonzero) digits is 21600, while the sum is 30.
Adding to 51305403423 its reverse (32430450315), we get a palindrome (83735853738).
The spelling of 51305403423 in words is "fifty-one billion, three hundred five million, four hundred three thousand, four hundred twenty-three".
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