51311244013 has 4 divisors (see below), whose sum is σ = 51651053728. Its totient is φ = 50971434300.

The previous prime is 51311244001. The next prime is 51311244043. The reversal of 51311244013 is 31044211315.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-51311244013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51311244043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 169904631 + ... + 169904932.

It is an arithmetic number, because the mean of its divisors is an integer number (12912763432).

Almost surely, 2^51311244013 is an apocalyptic number.

It is an amenable number.

51311244013 is a deficient number, since it is larger than the sum of its proper divisors (339809715).

51311244013 is a wasteful number, since it uses less digits than its factorization.

51311244013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 339809714.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 51311244013 its reverse (31044211315), we get a palindrome (82355455328).

The spelling of 51311244013 in words is "fifty-one billion, three hundred eleven million, two hundred forty-four thousand, thirteen".