Base | Representation |
---|---|
bin | 1001100011101101… |
… | …00111011000111111 |
3 | 111020121120111120122 |
4 | 10301312213120333 |
5 | 41002112233444 |
6 | 2205103005155 |
7 | 241105623362 |
oct | 46166473077 |
9 | 14217514518 |
10 | 5131367999 |
11 | 21a35837aa |
12 | bb25997bb |
13 | 63a135c34 |
14 | 3696da0d9 |
15 | 2007554ee |
hex | 131da763f |
5131367999 has 4 divisors (see below), whose sum is σ = 5139299664. Its totient is φ = 5123436336.
The previous prime is 5131367993. The next prime is 5131368089. The reversal of 5131367999 is 9997631315.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5131367999 - 212 = 5131363903 is a prime.
It is a super-2 number, since 2×51313679992 = 52661875082322528002, which contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 5131367999.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5131367993) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3964862 + ... + 3966155.
It is an arithmetic number, because the mean of its divisors is an integer number (1284824916).
Almost surely, 25131367999 is an apocalyptic number.
5131367999 is a deficient number, since it is larger than the sum of its proper divisors (7931665).
5131367999 is an equidigital number, since it uses as much as digits as its factorization.
5131367999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7931664.
The product of its digits is 1377810, while the sum is 53.
The square root of 5131367999 is about 71633.5675434359. The cubic root of 5131367999 is about 1724.8224138685.
The spelling of 5131367999 in words is "five billion, one hundred thirty-one million, three hundred sixty-seven thousand, nine hundred ninety-nine".
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