Base | Representation |
---|---|
bin | 1001100011101101… |
… | …01001101001010001 |
3 | 111020121120222020122 |
4 | 10301312221221101 |
5 | 41002113032413 |
6 | 2205103120025 |
7 | 241105662323 |
oct | 46166515121 |
9 | 14217528218 |
10 | 5131377233 |
11 | 21a358a734 |
12 | bb25a3015 |
13 | 63a13a1b8 |
14 | 3696dd613 |
15 | 200758108 |
hex | 131da9a51 |
5131377233 has 4 divisors (see below), whose sum is σ = 5240555520. Its totient is φ = 5022198948.
The previous prime is 5131377221. The next prime is 5131377259. The reversal of 5131377233 is 3327731315.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3327731315 = 5 ⋅665546263.
It is a cyclic number.
It is not a de Polignac number, because 5131377233 - 216 = 5131311697 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5131377193 and 5131377202.
It is not an unprimeable number, because it can be changed into a prime (5131377203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54589073 + ... + 54589166.
It is an arithmetic number, because the mean of its divisors is an integer number (1310138880).
Almost surely, 25131377233 is an apocalyptic number.
It is an amenable number.
5131377233 is a deficient number, since it is larger than the sum of its proper divisors (109178287).
5131377233 is a wasteful number, since it uses less digits than its factorization.
5131377233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 109178286.
The product of its digits is 39690, while the sum is 35.
The square root of 5131377233 is about 71633.6319964303. The cubic root of 5131377233 is about 1724.8234484854.
The spelling of 5131377233 in words is "five billion, one hundred thirty-one million, three hundred seventy-seven thousand, two hundred thirty-three".
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