Base | Representation |
---|---|
bin | 1110111011110100011… |
… | …01000000111000010101 |
3 | 1211001112101210000020011 |
4 | 13131322031000320111 |
5 | 31401413220340203 |
6 | 1031423302040221 |
7 | 52034240264542 |
oct | 7357215007025 |
9 | 1731471700204 |
10 | 513151340053 |
11 | 18869860a980 |
12 | 83551419071 |
13 | 3950b99a5b1 |
14 | 1ab9db05bc9 |
15 | d5354cb76d |
hex | 777a340e15 |
513151340053 has 16 divisors (see below), whose sum is σ = 560748988800. Its totient is φ = 465712044480.
The previous prime is 513151340029. The next prime is 513151340059. The reversal of 513151340053 is 350043151315.
It is a cyclic number.
It is not a de Polignac number, because 513151340053 - 217 = 513151208981 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 513151339997 and 513151340024.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (513151340059) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29897088 + ... + 29914246.
It is an arithmetic number, because the mean of its divisors is an integer number (35046811800).
Almost surely, 2513151340053 is an apocalyptic number.
It is an amenable number.
513151340053 is a deficient number, since it is larger than the sum of its proper divisors (47597648747).
513151340053 is a wasteful number, since it uses less digits than its factorization.
513151340053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21612.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 513151340053 its reverse (350043151315), we get a palindrome (863194491368).
The spelling of 513151340053 in words is "five hundred thirteen billion, one hundred fifty-one million, three hundred forty thousand, fifty-three".
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