Base | Representation |
---|---|
bin | 111010010110000010000100… |
… | …1011010110000010010011111 |
3 | 2111022002120210021201222121022 |
4 | 1310230010021122300102133 |
5 | 1014231243140320141343 |
6 | 5015253303342554355 |
7 | 213045404501134622 |
oct | 16454041132602237 |
9 | 2438076707658538 |
10 | 513201505240223 |
11 | 139581599632a48 |
12 | 49685a818989bb |
13 | 19048904476757 |
14 | 90a312a42bdb9 |
15 | 3e4e83773b568 |
hex | 1d2c1096b049f |
513201505240223 has 2 divisors, whose sum is σ = 513201505240224. Its totient is φ = 513201505240222.
The previous prime is 513201505240189. The next prime is 513201505240283. The reversal of 513201505240223 is 322042505102315.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 513201505240223 - 28 = 513201505239967 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (513201505240283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256600752620111 + 256600752620112.
It is an arithmetic number, because the mean of its divisors is an integer number (256600752620112).
Almost surely, 2513201505240223 is an apocalyptic number.
513201505240223 is a deficient number, since it is larger than the sum of its proper divisors (1).
513201505240223 is an equidigital number, since it uses as much as digits as its factorization.
513201505240223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 35.
The spelling of 513201505240223 in words is "five hundred thirteen trillion, two hundred one billion, five hundred five million, two hundred forty thousand, two hundred twenty-three".
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