Base | Representation |
---|---|
bin | 1110111011111010101… |
… | …11001100011011000111 |
3 | 1211001200002111201001211 |
4 | 13131331113030123013 |
5 | 31402020302343143 |
6 | 1031432434032251 |
7 | 52035452626555 |
oct | 7357527143307 |
9 | 1731602451054 |
10 | 513204340423 |
11 | 18871551a935 |
12 | 83567118687 |
13 | 39519966568 |
14 | 1aba6b80bd5 |
15 | d539e9a49d |
hex | 777d5cc6c7 |
513204340423 has 16 divisors (see below), whose sum is σ = 543212602240. Its totient is φ = 484212538656.
The previous prime is 513204340399. The next prime is 513204340447. The reversal of 513204340423 is 324043402315.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (513204340399) and next prime (513204340447).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-513204340423 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (513204340123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 939165 + ... + 1381462.
It is an arithmetic number, because the mean of its divisors is an integer number (33950787640).
Almost surely, 2513204340423 is an apocalyptic number.
513204340423 is a deficient number, since it is larger than the sum of its proper divisors (30008261817).
513204340423 is a wasteful number, since it uses less digits than its factorization.
513204340423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2320846.
The product of its (nonzero) digits is 34560, while the sum is 31.
Adding to 513204340423 its reverse (324043402315), we get a palindrome (837247742738).
The spelling of 513204340423 in words is "five hundred thirteen billion, two hundred four million, three hundred forty thousand, four hundred twenty-three".
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