Base | Representation |
---|---|
bin | 1110111011111011100… |
… | …01100100011000101010 |
3 | 1211001200120111222010212 |
4 | 13131331301210120222 |
5 | 31402024040114224 |
6 | 1031433242141122 |
7 | 52035565453643 |
oct | 7357561443052 |
9 | 1731616458125 |
10 | 513211254314 |
11 | 1887194123a0 |
12 | 835694b17a2 |
13 | 3951b217515 |
14 | 1aba7a606ca |
15 | d53a8b3d0e |
hex | 777dc6462a |
513211254314 has 8 divisors (see below), whose sum is σ = 839800234368. Its totient is φ = 233277842860.
The previous prime is 513211254313. The next prime is 513211254319. The reversal of 513211254314 is 413452112315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×5132112543143 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (513211254313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11663892122 + ... + 11663892165.
It is an arithmetic number, because the mean of its divisors is an integer number (104975029296).
Almost surely, 2513211254314 is an apocalyptic number.
513211254314 is a deficient number, since it is larger than the sum of its proper divisors (326588980054).
513211254314 is a wasteful number, since it uses less digits than its factorization.
513211254314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23327784300.
The product of its digits is 14400, while the sum is 32.
Adding to 513211254314 its reverse (413452112315), we get a palindrome (926663366629).
The spelling of 513211254314 in words is "five hundred thirteen billion, two hundred eleven million, two hundred fifty-four thousand, three hundred fourteen".
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