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513212441 = 773316063
BaseRepresentation
bin11110100101110…
…000000000011001
31022202200220010012
4132211300000121
52022340244231
6122531531305
715501143120
oct3645600031
91282626105
10513212441
11243771115
12123a59b35
138242cc01
144c234ab7
15300c7e2b
hex1e970019

513212441 has 4 divisors (see below), whose sum is σ = 586528512. Its totient is φ = 439896372.

The previous prime is 513212437. The next prime is 513212467. The reversal of 513212441 is 144212315.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 513212441 - 22 = 513212437 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (513202441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36658025 + ... + 36658038.

It is an arithmetic number, because the mean of its divisors is an integer number (146632128).

Almost surely, 2513212441 is an apocalyptic number.

It is an amenable number.

513212441 is a deficient number, since it is larger than the sum of its proper divisors (73316071).

513212441 is an equidigital number, since it uses as much as digits as its factorization.

513212441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 73316070.

The product of its digits is 960, while the sum is 23.

The square root of 513212441 is about 22654.1925700299. The cubic root of 513212441 is about 800.6309818840.

Adding to 513212441 its reverse (144212315), we get a palindrome (657424756).

The spelling of 513212441 in words is "five hundred thirteen million, two hundred twelve thousand, four hundred forty-one".

Divisors: 1 7 73316063 513212441