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51322544513437 is a prime number
BaseRepresentation
bin10111010101101011101100…
…00010001110000110011101
320201201101110100222122212011
423222311312002032012131
523211332032343412222
6301053130152111221
713544634332332111
oct1352656602160635
9221641410878764
1051322544513437
111539785044696a
12590a7a0395511
13228390640b4a2
14c9604ad95741
155e003cdc0c77
hex2ead7608e19d

51322544513437 has 2 divisors, whose sum is σ = 51322544513438. Its totient is φ = 51322544513436.

The previous prime is 51322544513423. The next prime is 51322544513459. The reversal of 51322544513437 is 73431544522315.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 51319256752516 + 3287760921 = 7163746^2 + 57339^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51322544513437 is a prime.

It is a super-3 number, since 3×513225445134373 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51322544573437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25661272256718 + 25661272256719.

It is an arithmetic number, because the mean of its divisors is an integer number (25661272256719).

Almost surely, 251322544513437 is an apocalyptic number.

It is an amenable number.

51322544513437 is a deficient number, since it is larger than the sum of its proper divisors (1).

51322544513437 is an equidigital number, since it uses as much as digits as its factorization.

51322544513437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6048000, while the sum is 49.

The spelling of 51322544513437 in words is "fifty-one trillion, three hundred twenty-two billion, five hundred forty-four million, five hundred thirteen thousand, four hundred thirty-seven".