Base | Representation |
---|---|
bin | 1110111011111101111… |
… | …01101100110001101111 |
3 | 1211001201222001220102202 |
4 | 13131332331230301233 |
5 | 31402044142233011 |
6 | 1031435234012115 |
7 | 52036230214355 |
oct | 7357675546157 |
9 | 1731658056382 |
10 | 513231211631 |
11 | 188729703646 |
12 | 8357411703b |
13 | 395223b4398 |
14 | 1abaa5777d5 |
15 | d53c50723b |
hex | 777ef6cc6f |
513231211631 has 2 divisors, whose sum is σ = 513231211632. Its totient is φ = 513231211630.
The previous prime is 513231211531. The next prime is 513231211657. The reversal of 513231211631 is 136112132315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 513231211631 - 230 = 512157469807 is a prime.
It is a super-2 number, since 2×5132312116312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 513231211594 and 513231211603.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (513231211331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256615605815 + 256615605816.
It is an arithmetic number, because the mean of its divisors is an integer number (256615605816).
Almost surely, 2513231211631 is an apocalyptic number.
513231211631 is a deficient number, since it is larger than the sum of its proper divisors (1).
513231211631 is an equidigital number, since it uses as much as digits as its factorization.
513231211631 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3240, while the sum is 29.
Adding to 513231211631 its reverse (136112132315), we get a palindrome (649343343946).
The spelling of 513231211631 in words is "five hundred thirteen billion, two hundred thirty-one million, two hundred eleven thousand, six hundred thirty-one".
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