Base | Representation |
---|---|
bin | 100101010101111101110… |
… | …1111001100010001110111 |
3 | 200011122122210011210021101 |
4 | 1022223323233030101313 |
5 | 1133042141041404303 |
6 | 14525444300430531 |
7 | 1036543004423266 |
oct | 112537357142167 |
9 | 20148583153241 |
10 | 5132414403703 |
11 | 16a9710146954 |
12 | 6aa843248447 |
13 | 2b2ca5228832 |
14 | 13a5a57805dd |
15 | 8d78c503d1d |
hex | 4aafbbcc477 |
5132414403703 has 2 divisors, whose sum is σ = 5132414403704. Its totient is φ = 5132414403702.
The previous prime is 5132414403661. The next prime is 5132414403713. The reversal of 5132414403703 is 3073044142315.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5132414403703 is a prime.
It is a super-2 number, since 2×51324144037032 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5132414403713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2566207201851 + 2566207201852.
It is an arithmetic number, because the mean of its divisors is an integer number (2566207201852).
Almost surely, 25132414403703 is an apocalyptic number.
5132414403703 is a deficient number, since it is larger than the sum of its proper divisors (1).
5132414403703 is an equidigital number, since it uses as much as digits as its factorization.
5132414403703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 37.
The spelling of 5132414403703 in words is "five trillion, one hundred thirty-two billion, four hundred fourteen million, four hundred three thousand, seven hundred three".
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